## How do you add numbers using pointers?

Program : How to Add Two Numbers Using Pointer?

- int main() {
- int *ptr1, *ptr2;
- int num;
- printf(“\nEnter two numbers : “);
- scanf(“%d %d”, ptr1, ptr2);
- num = *ptr1 + *ptr2;
- printf(“Sum = %d”, num);
- return (0);

**How do you find the sum of arrays using pointers?**

The sequence of steps for the solution will be as follows:

- Create a pointer variable, which points to an integer data.
- Take a number i.e size of array as input.
- Create a block of space fo size (size-of-array*sizeof(int)) using malloc() assigning the starting address of this whole space to the pointer variable.

**How do you find the sum of two pointers?**

A pointer in programming holds the address of a variable….Algorithm:

- Initialize two integer variables.
- Initialize two integer pointers.
- Reference the pointers to variables using ‘&’ operator.
- Now, using * operator, access the address pointed by pointers.
- Add the values, and store it.
- Print the sum.

### How do I add a value to a pointer?

Add an integer to a pointer or subtract an integer from a pointer. The effect of p+n where p is a pointer and n is an integer is to compute the address equal to p plus n times the size of whatever p points to (this is why int * pointers and char * pointers aren’t the same). Subtract one pointer from another.

**Can we add two pointers?**

Pointers contain addresses. Adding two addresses makes no sense, because you have no idea what you would point to. Subtracting two addresses lets you compute the offset between these two addresses, which may be very useful in some situations. Adding two pointers makes no sense: there should be a type “pointer offset”.

**How do you add two numbers with function and pointer?**

Logic To Add Two Numbers using Pointers and Function We ask the user to enter 2 numbers and store it inside address of variables a and b. Next we pass the values of a and b and address of variable c to a function called addition(). And then print the result in main method itself.

#### How do I reverse a string pointer?

Reverse a string using pointers

- #include
- #include
- char *s;
- int len,i;
- printf(“\nENTER A STRING: “);
- gets(s);
- len=strlen(s);
- printf(“\nTHE REVERSE OF THE STRING IS:”);

**Can we add pointers together?**

No, you can t add pointers together.

**What does adding one to a pointer do?**

Pointer Arithmetic Unlike regular numbers, adding 1 to a pointer will increment its value (a memory address) by the size of its underlying data type. Apart from adding integer to a pointer, we can also subtract them, and as long as they’re the same type, we can subtract a pointer from another pointer.

## Why is two pointers impossible?

Pointer Arithmetic on Arrays: Adding two addresses makes no sense because there is no idea what it would point to. Subtracting two addresses lets you compute the offset between the two addresses.

**How to write C program to find sum of n numbers?**

How to write a C Program to find Sum of N Numbers using For Loop, While Loop, Do While Loop, Functions, and Recursion. This C program allows the user to enter any integer value. By using the For loop, this program calculates the sum of N natural numbers.

**How to find sum of elements in array using pointers?**

The below given C program will find the sum of all elements in array using pointers. Kindly check out the program to find the sum of all elements in array using pointers * Write a c program to check whether a given number is prime number or not?

### How to find the sum of the integers N2?

n 2. n^2. n2. There are several ways to solve this problem. One way is to view the sum as the sum of the first n n even integers. The sum of the first 2 n ( 2 n + 1) 2 − 2 ( n ( n + 1) 2) = n ( 2 n + 1) − n ( n + 1) = n 2. ) = n(2n+1)− n(n+ 1) = n2. n n positive integers.

**How to find sum and average of n numbers?**

Above is the source code for C Program to find sum and average of n numbers using pointers which is successfully compiled and run on Windows System.The Output of the program is shown above .